Hi Ray,
Could you please explain why you choose a Zerner diode and resistor combination for adjustable LM2596, instead of a fixed 5 volt output LM2596, or even using 2 resistor as a voltage divider for output of adjustable LM2596, like it mentioned in TI data-sheet. I am still having problem with my circuit, seeing 1.8 volt only, I ordered anew part from Digikey to try. I appreciate any clue to solve my issue,
Thanks